\(\left(x-2\right)^2=16\)
=> \(x-2=4\) hoặc \(x-2=-4\)
=> \(x=4+2=6\) hoặc \(x=-4+2=-2\)
Vậy x = 6 hoặc x = -2
\(\left(x-2\right)^2=16\)
=> \(x-2=4\) hoặc \(x-2=-4\)
=> \(x=4+2=6\) hoặc \(x=-4+2=-2\)
Vậy x = 6 hoặc x = -2
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)
Tìm x biết :
\(\left(\frac{x-2}{12}\right)+\left(\frac{x-2}{20}\right)+\left(\frac{x-2}{30}\right)+\left(\frac{x-2}{42}\right)+\left(\frac{x-2}{56}\right)+\left(\frac{x-2}{72}\right)=\frac{16}{9}\)
giúp mk nha
\(\dfrac{\left(-2\right)^x}{16}=-8\)
tìm x biết
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
Tìm x biết: \(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
timd x \(x+\left\{-x-\left[-x-\left(-x\right)\right]\right\}=-16\)16
\(x+\left\{\left(x+3\right)-\left[\left(x+3\right)-\left(-x-2\right)\right]\right\}=x\)
Tìm x
a) \(\left(19.x+2.5^1\right):14=\left(13-8\right)^2-4^2\)
b) \(-\left(x+84\right)+213=-16\)
Tìm x
\(\left(X+\frac{1}{2}\right)+\left(X+\frac{1}{4}\right)+\left(X+\frac{1}{8}\right)+\left(X+\frac{1}{16}\right)=1\)
giúp mình giải nhé
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
\(1.\)Tìm x biết :
\(a)\left(2x-1\right).\left(y-2\right)=13\)
\(b)x.\left(y-2\right)=16\)