\(\dfrac{\left(-2\right)^x}{16}=-8\\ \Leftrightarrow\left(-2\right)^x=-8.16=\left(-2\right)^3.\left(-2\right)^4=\left(-2\right)^{3+4}=\left(-2\right)^7\\ Vậy:x=7\)
\(\dfrac{\left(-2\right)^x}{16}=-8\\ \Leftrightarrow\left(-2\right)^x=-8.16=\left(-2\right)^3.\left(-2\right)^4=\left(-2\right)^{3+4}=\left(-2\right)^7\\ Vậy:x=7\)
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
Tìm x biết: a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\) b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)
c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\) d) \(x+\dfrac{1}{3}=\dfrac{-12}{5}.\dfrac{10}{6}\)
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)
Tìm x, biết:
\(a,\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(b,\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\)
\(c,\dfrac{x}{8}=\dfrac{9}{4}\)
\(d,\dfrac{x-3}{2}=\dfrac{18}{x-3}\)
\(e,4,5x-6,2x=6,12\)
\(h,11,4-\left(x-3,4\right)=-16,2\)
\(\left(x^2-1\dfrac{9}{16}\right).\left(x^3+\dfrac{1}{8}\right)=0\)
giúp mik với ạ
Tìm x biết: a) \(\dfrac{6}{-x}=\dfrac{x}{-24}\) b) \(x-\dfrac{7}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
c)\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\) d) \(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
e) \(\dfrac{9}{x}=\dfrac{-35}{105}\) f) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
Tìm x, biết
\(\left|x\right|-\dfrac{5}{6}.x=\dfrac{4}{9}.\dfrac{15}{8}\)
Tìm các số nguyên x, y, z, t biết : \(\dfrac{24}{4}=\dfrac{-x}{3}=\dfrac{3}{y^2}=\dfrac{\left(z+3\right)^3}{-4}=\dfrac{\left||t|-2\right|}{8}\)
Tìm x:
\(\dfrac{3}{8}\left(x-\dfrac{2}{3}\right)-\dfrac{2}{9}.\left(3x-\dfrac{1}{2}\right)=-\dfrac{7}{36}\)