\(\frac{x+1}{2019}+\frac{x+2}{2018}+\frac{x+3}{2017}=3\)
\(\Leftrightarrow\left(\frac{x+1}{2019}+1\right)+\left(\frac{x+2}{2018}+1\right)+\left(\frac{x+3}{2017}+1\right)=0\)
\(\Leftrightarrow\frac{x+2020}{2019}+\frac{x+2020}{2018}+\frac{x+2020}{2017}=0\)
\(\Leftrightarrow\left(x+2020\right)\left(\frac{1}{2019}+\frac{1}{2018}+\frac{1}{2017}\right)=0\)
\(\Leftrightarrow x+2020=0\)( vì \(\frac{1}{2019}+\frac{1}{2018}+\frac{1}{2017}>0\) )
\(\Leftrightarrow x=-2020\)
Vậy ...
Tìm x biết \(\frac{x-1}{2017}+\frac{x-2}{2018}-\frac{x-3}{2019}=\frac{x-4}{2020}\)
\(\frac{x-1}{2019}+\frac{x-2}{2018}=\frac{x-3}{2017}+\frac{x-4}{2016}\)
Tìm x biết:
a) \(\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
b) \(\frac{x+4}{2016}+\frac{x+3}{2017}=\frac{x+2}{2018}+\frac{x+1}{2019}\)
Tìm x biết:
\(\frac{x+1}{2019}+\)\(\frac{x+2}{2018}\)\(=\frac{x+3}{2017}+\)\(\frac{x+4}{2016}\)
Tìm x
\(\frac{x-2017}{2015.2016}+\frac{x-2018}{2016.2017}+\frac{x-2019}{2017.2018}+\frac{x-2020}{2018.1019}=\frac{1}{2015}+\frac{1}{2016}+\frac{1}{2017}+\frac{1}{1018}\)
Tìm x biết
\(\frac{x-1}{2019}\)+ \(\frac{x-2}{2018}\)- \(\frac{x-3}{2017}\)= \(\frac{x-4}{2016}\)
Tìm X biết ; \(\frac{X-1}{2019}\)+\(\frac{X-2}{2018}\)+\(\frac{X-3}{2017}\)+\(\frac{X-4}{2016}\).................+\(\frac{X-10}{2010}\) . CÁC BẠN GIÚP MÌNH VỚI .
Tìm x:
a) /2x+3/ = x+2
b) \(\left(x-7\right)^{x+2015}-\left(x-7\right)^{x+2016}=0\)
c) \(\frac{x+4}{2016}+\frac{x+3}{2017}=\frac{x+2}{2018}+\frac{x+1}{2019}\)
Tìm x: \(\frac{3-x}{2016}-1=\frac{2-x}{2017}+\frac{1-x}{2018}\)
