Question

tìm x

\(\dfrac{x}{-12}=\dfrac{-18}{x^2}\)

 

Answer 1

bài nãy ghi thiếu nên mik sửa lại câu

Answer 2

\(\dfrac{x}{-12}=\dfrac{-18}{x^2}\)

nên \(x^3=-216\)

hay x=-6

Answer 3

\(pt\Leftrightarrow\dfrac{x}{12}=\dfrac{18}{x^2}\Rightarrow x^3=216\Rightarrow x=6\)

Answer 4

\(\dfrac{x}{-12}=\dfrac{-18}{x^2}\)

<=> x . x² = -18 . (-12)

<=> x³ = 216

<=> x = 6