Question

Tìm x

(\(\dfrac{1}{2}\).x -5).(3x²-15)=0

Answer 1

\(\left[{}\begin{matrix}\dfrac{1}{2}x-5=0\\3x^2-15=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}\dfrac{1}{2}x=5\\3x^2=15\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=10\\x=\sqrt{5}\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow x\in\left\{10;\sqrt{5};-\sqrt{5}\right\}\)

Answer 3

TH1: \(\dfrac{1}{2}.x-5\) = 0

\(\dfrac{1}{2}x\) = 5

x = \(10\)

Th2: 3x² - 15 = 0

3 ( x² - 5 ) = 0

=> x² - 5 = 0

x² = 5

=> x = \(\sqrt{5}\) hoặc x = ( -\(\sqrt{5}\) )

Vậy x = 10 hoặc x = \(\sqrt{5}\) hoặc x = (  - \(\sqrt{5}\) )