`x^2+3x-10=0
`<=>x^2+5x-2x-10=0`
`<=>(x^2+5x)-(2x+10)=0`
`<=>x(x+5)-2(x+5)=0`
`<=>(x-2)(x+5)=0`
$\Leftrightarrow\left[\begin{array}{1}x-2=0\\x+5=0\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=2\\x=-5\end{array}\right.$
Vậy $x\in\{2;-5\}$