\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
\(\Rightarrow\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)
\(\Rightarrow x\left(\frac{1}{3}+\frac{2}{5}\right)=0-\frac{2}{5}\)
\(\Rightarrow x.\frac{11}{15}=-\frac{2}{5}\)
\(\Rightarrow x=-\frac{2}{5}:\frac{11}{15}\)
\(\Rightarrow x=-\frac{6}{11}\)
Vậy \(x=-\frac{6}{11}\)
\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
\(\Leftrightarrow\) \(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)
\(\Leftrightarrow\) \(\frac{11}{15}x=\frac{-2}{5}\)
\(\Leftrightarrow\) \(x=\frac{-6}{11}\)
Vậy x=-6/11
\(\Leftrightarrow\)
\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
\(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)
\(x\left(\frac{1}{3}+\frac{2}{5}\right)=-\frac{2}{5}\)
\(x\left(\frac{5}{15}-\frac{6}{15}\right)=-\frac{2}{5}\)
\(-\frac{1}{15}x=-\frac{2}{5}\)
\(x=-\frac{2}{5}:\left(-\frac{1}{15}\right)\)
\(x=-\frac{2}{5}.\left(-15\right)\)
\(x=6\)
Vậy \(x=6\)
Xin lỗi b
B tham khảo bài của miyano shiho nhé
bài mk sai rồi.
\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
<=> \(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)
<=> \(\frac{2}{5}x-\frac{1}{15}=0\)
<=> \(\frac{2}{5}x=\frac{1}{15}\)
<=> \(x=\frac{1}{6}\)
