Question

Tìm x

a)\(\left(x+1\right)^2=x+1\)

b)\(\left(x-2\right)^3-\left(x-3\right).\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)

Giúp em với ạ ! Em cảm ơn !!

 

Answer 1

a) \(\left(x+1\right)^2=x+1\)

\(\left(x+1\right)^2-\left(x+1\right)=0\)

\(\left(x+1\right)\left(x+1-1\right)=0\)

\(x\left(x+1\right)=0\)

\(x=0\) hoặc \(x+1=0\)

*) \(x+1=0\)

\(x=-1\)

Vậy \(x=-1\); \(x=0\)

Answer 2

a: =>(x+1)(x+1-1)=0

=>x=0 hoặc x=-1

b: \(\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\)

=>24x+25=49

=>x=1