\(a,4x^2=1\\ x^2=\dfrac{1}{4}\\ \left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\\ ------\\ b,2x^2=0,18\\ x^2=\dfrac{9}{100}\\ \left[{}\begin{matrix}x=\dfrac{3}{10}\\x=-\dfrac{3}{10}\end{matrix}\right.\\ -----\\ c,đkx\ge0\\ \dfrac{5}{12}\sqrt{x}=\dfrac{1}{3}+\dfrac{1}{6}\\ \dfrac{5}{12}\sqrt{x}=\dfrac{1}{2}\\ \sqrt{x}=\dfrac{6}{5}\\ x=\dfrac{36}{25}\left(thoaman\right)\\ \)
\(-----------\\ d,đkx\ge0\\ \left[{}\begin{matrix}\sqrt{x}+4=0\\x-6\sqrt{x}=0\end{matrix}\right.=>\left[{}\begin{matrix}\sqrt{x}=-4\left(voli\right)\\\sqrt{x}\left(\sqrt{x}-6\right)=0\end{matrix}\right.\\ =>\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{x}-6=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\left(thoaman\right)\\x=36\left(thoaman\right)\end{matrix}\right.\)
a: =>(2x-1)(2x+1)=0
=>x=1/2 hoặc x=-1/2
b: =>2x^2=0,18
=>x^2=0,09
=>x=0,3 hoặc x=-0,3
c: \(\Leftrightarrow\sqrt{x}\cdot\dfrac{5}{12}=\dfrac{1}{6}+\dfrac{1}{3}=\dfrac{3}{6}=\dfrac{1}{2}\)
=>căn x=1/2:5/12=1/2x12/5=12/10=6/5
=>x=36/25
