a) ( x- 55 ) . 17 = 0
x - 55 = 0 : 17
x - 55 = 0
x = 0 + 55
x = 55
Vậy x = 55
b) 25 . ( x - 75 ) = 25
x - 75 = 25 : 25
x - 75 = 1
x = 1 + 75
x = 76
Vậy x = 76
c) ( x - 5 ) ( x - 7 ) = 0
=> x - 5 = 0 hoặc x - 7 = 0
x = 0 + 5 x = 0 + 7
x = 5 x = 7
Vậy \(x\in\left\{5;7\right\}\)
d) ( x -11 ) ( x + 17 ) = 0
=> x - 11 = 0 hoặc x + 17 = 0
x = 0 + 11 x = 0 - 17
x = 11 x = -17
Vậy \(x\in\left\{11;-17\right\}\)
a,( x-55).17=0
x-55=0:17
x-55=0
x=0+55
x=55
b,25.(x-75)=25
x-75=25:25
x-75=1
x=75+1
x=76
c, (x-5).(x-7)=0
x-5=0
x=0+5
x=5
hoặc
x-7=0
x=0+7
x=7
kl ....
d, (x-11).(x+17)=0
x-11=0
x=0+11
x=11
hoặc
x+17=0
x=0-17
x=-17
hc tốt ~:B~
a)(x-55).17=0
=>x- 55 = 0:17
=> x- 55 =0
=> x = 0 + 55
=> x =55
vậy x = 55
b) 25.(x-75) = 25
=> x - 75 =25 : 25
=> x - 75= 1
=> x = 1+75
=> x = 76
vậy x = 76
c)(x-5) . ( x-7) = 0
=> x-5 = 0 hay x-7 =0
=> x = 0 + 5 x = 0 + 7
=> x = 5 x = 7
vậy x = 5 hay x= 7
d) ( x-11 ) . ( x + 17 ) = 0
=> x - 11 = 0 hay x + 17 = 0
=> x - = 0+ 11 => x = 0 -17
=> x = 11 => x =-17
vậy x = 11 hay x= -17
hok tốt
a)(x-55).17=0
=>x- 55 = 0:17
=> x- 55 =0
=> x = 0 + 55
=> x =55
vậy x = 55
b) 25.(x-75) = 25
=> x - 75 =25 : 25
=> x - 75= 1
=> x = 1+75
=> x = 76
vậy x = 76
c)(x-5) . ( x-7) = 0
=> x-5 = 0 hay x-7 =0
=> x = 0 + 5 x = 0 + 7
=> x = 5 x = 7
vậy x = 5 hay x= 7
d) ( x-11 ) . ( x + 17 ) = 0
=> x - 11 = 0 hay x + 17 = 0
=> x - = 0+ 11 => x = 0 -17
=> x = 11 => x =-17
vậy x = 11 hay x= -17
a,(x-55).17=0
x-55=0
x=0+55
x=55
b,25.(x-75)=25
x-75=25:25
x-75=1
x=75+1
x=76
c, (x-5).(x-7)=0
x-5=0
x=0+5
x=5
hoặc
x-7=0
x=0+7
x=7
kl ....
d, (x-11).(x+17)=0
x-11=0
x=0+11
x=11
hoặc
x+17=0
x=0-17
x=-17
a) (x-55).17=0
<=> x-55=0
<=> x=0+55
<=> x=55
Vậy...
b) 25(x-75)=25
<=> x-75=1
<=>x=76
Vậy..
(x-5)(x-7)=0
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-7=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=7\end{cases}}}\)
vậy .........
\(\left(x-11\right)\left(x+17\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-11=0\\x+17=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-17\end{cases}}\)
Vậy....
