a)
(x2-x+1)(x+1)-x2+3x=15
x(x2-x+1)+1(x2-x+1)-x2+3x=15
x3-x2+x+x2-x+1-x2+3x=15
x3+(-x2+x2-x2)+(x-x+3x)=15
x3-x2+3x=15
x2(x-1)+3x=15
x2(x-1)+(3x-3)=12
x2(x-1)+3(x-1)=12
(x2+3)(x-1)=12
Thử lần lượt nha
b)(x2-5)(x+2)+5x=2x+17
x(x2-5)+2(x2-5)+5x-2x=17
x3-5x+2x2-10+3x=17
x3+2x2-2x=17
x2(x+2)-2x-4=13
x2(x+2)-2(x+2)=13
(x2-2)(x+2)=13
Thử lần lượt nha bạn