a: \(\Leftrightarrow8x\left(x-3\right)\left(x+3\right)=0\)
hay \(x\in\left\{0;3;-3\right\}\)
b: \(\Leftrightarrow x^2-4x+4-x^2-2x+3=12\)
=>-6x=5
hay x=-5/6
Tìm \(x\):
\(8\)) \(1-\left(x-6\right)=4\left(2-2x\right)\)
\(9\))\(\left(3x-2\right)\left(x+5\right)=0\)
\(10\))\(\left(x+3\right)\left(x^2+2\right)=0\)
\(11\))\(\left(5x-1\right)\left(x^2-9\right)=0\)
\(12\))\(x\left(x-3\right)+3\left(x-3\right)=0\)
\(13\))\(x\left(x-5\right)-4x+20=0\)
\(14\))\(x^2+4x-5=0\)
Tìm x biết:
\(a.\left(x+1\right)\left(x^2-x+1\right)-x\left(x^2-5\right)=71\)
\(b.\left(2x-3\right)^3-8x\left(x-1\right)^2+4x\left(4x+1\right)+27=0\)
Chứng minh rằng biểu thức sau không phụ thuộc vào biến x:
a/A= \(\left(x+4\right)\left(x-4\right)-2x\left(3+x\right)+\left(x+3\right)^2\)
b/B=\(\left(x^2+4\right)\left(x+2\right)\left(x-2\right)-\left(x^2+3\right)\left(x^2-3\right)\)
tìm x:
a) \(\left(2x+5\right)\left(4x-10\right)+4x.\left(3-2x\right)^2=0\)
b) \(\left(2x-3\right)^2-\left(3x+1\right)^2=0\)
Tìm x :
a)\(x\left(8x-2\right)-8x^2+12=0\)
b) \(x\left(4x-5\right)-\left(2x+1\right)^2=0\)
\(8x^3.\left(x-1\right)^3+24x^2.\left(x-1\right)^2+8x^3-351\left(x-1\right)^3=0\)
A)\(\left(2x-7\right)^2-6\left(2x-7\right)\left(x-3\right)=0\)
B) \(x^3+1+\left(x^2-x+1\right)=0\)
C) \(\left(3x+1\right)^2-x^2+8x-16=0\)
D)\(\left(x+1\right)\left(x-1\right)^2\left(x+1\right)\left(x-2\right)^2=0\)
E) \(\left(3x+1\right)\left(x-3\right)^2=\left(3x+1\right)\left(2x-5\right)^2\)
F) \(\left(x+5\right)\left(3x+2\right)^2=x^2\left(x+5\right)\)
Giải PT: \(48x\left(x+1\right)\left(x^3-4\right)=\left(x^4+8x+12\right)^2\)
Tìm x, biết :
a/ \(\dfrac{1}{3}x\left(x^2-4\right)=0\)
b/ \(x\left(x+5\right)=x+5\)
c/ \(x^3-\dfrac{1}{9}x=0\)
3)\(^2-\left(x+5\right)^2=0\)
e/ \(\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)
f/ \(x\left(2x-3\right)-6+4x=0\)
g/ \(2\left(3x-2\right)^2-9x^2+4=0\)
h/ \(x^2\left(x+1\right)+2x\left(x+1\right)=0\)
i/ \(4x^2+9x+5=0\)
