Question

tìm x

a) 1313/2828 + x = 2323/4646

b) 23/69 - x = 17 / 153

Answer 1

a)\(\Leftrightarrow\)\(x=\dfrac{2323}{4646}-\dfrac{1313}{2828}\)

\(\Leftrightarrow\)\(x=\dfrac{1}{28}\)

b)\(\Leftrightarrow\)\(x=\dfrac{23}{69}-\dfrac{17}{153}\)

\(\Leftrightarrow\)\(x=\dfrac{2}{9}\)

 

Answer 2

a) \(\dfrac{1313}{2828}\) + \(x\) = \(\dfrac{2323}{4646}\)

\(\dfrac{13}{28}\) + \(x\) = \(\dfrac{1}{2}\)

\(x=\dfrac{1}{2}-\dfrac{13}{28}\)

\(x=\dfrac{14}{28}-\dfrac{13}{28}\)

\(x=\dfrac{1}{28}\)

Answer 3

b) \(\dfrac{23}{69}-x=\dfrac{17}{153}\)

\(\dfrac{1}{3}-x=\dfrac{1}{9}\)

\(x=\dfrac{1}{9}+\dfrac{1}{3}\)

\(x=\dfrac{1}{9}+\dfrac{3}{9}\)

\(x=\dfrac{4}{9}\)

Answer 4

a: Ta có: \(x+\dfrac{1313}{2828}=\dfrac{2323}{4646}\)

\(\Leftrightarrow x+\dfrac{13}{28}=\dfrac{1}{2}\)

hay \(x=\dfrac{1}{28}\)

b: Ta có: \(\dfrac{23}{69}-x=\dfrac{17}{153}\)

\(\Leftrightarrow\dfrac{1}{3}-x=\dfrac{1}{9}\)

hay \(x=\dfrac{2}{9}\)