\(x:\dfrac{6}{8}=\dfrac{15}{x}\)
\(\Leftrightarrow x^2=\dfrac{45}{4}\)
hay \(x\in\left\{\dfrac{3\sqrt{5}}{2};-\dfrac{3\sqrt{5}}{2}\right\}\)
\(x:\dfrac{6}{8}=\dfrac{15}{x}\)
<=> \(x.\dfrac{4}{3}=\dfrac{15}{x}\)
<=> \(\dfrac{4x}{3}=\dfrac{15}{x}\)
<=> 4x . x = 15 . 3
<=> 4x2 = 45
<=> x2 = \(\dfrac{45}{4}\)
<=> \(x=\dfrac{\sqrt{45}}{2}\)