\(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=5\)
\(\Rightarrow4x^2-20x-4x^2+7x-3=5\)
\(\Rightarrow-13x=8\)
\(\Rightarrow x=-\frac{8}{13}\)
nhân bung ra ta có
\(4x^2-20x-4x^2+7x-3\)=5
<=> \(-13x-3=5\)
=> x = \(\frac{-8}{13}\)
\(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=5\)
\(\Rightarrow4x^2-20x-4x^2+7x-3=5\)
\(\Rightarrow-13x-3=5\)
\(\Rightarrow-13x=8\)
\(\Rightarrow x=-\frac{8}{13}\)