Question

4x(x-5)-(x-1)(4x-3)=5 tìm x

 

Answer 1

4x(x-5)-(x-1)(4x-3) = 5

4x² - 20x - [4x² - 3x - (4x - 3)] = 5

4x² - 20x - [4x² - 3x - 4x + 3] = 5

4x² - 20x - 4x_² + 3x + 4x - 3 = 5

-13x = 5 + 3

-13x = 8

x = \(\dfrac{\left(-8\right)}{13}\)

Answer 2

4x(x - 5) - (x - 1)(4x - 3) = 5

<=> 4x² - 20x - 4x² + 3x + 4x - 3 = 5

<=> 4x² - 4x² - 20x + 3x + 4x = 5 + 3

<=> -13x = 8

<=> \(x=-\dfrac{8}{13}\)