4(x+3)-2(7-3x)=-3
<=> 4x + 12 - 14 + 6x = -3
<=> 4x + 6x = -3 - 12 + 14
<=> 10x = -1
<=> x = \(-\frac{1}{10}\)
\(4\left(x+3\right)-2\left(7-3x\right)=-3\)
\(4x+12-14+6x=-3\)
\(10x-2=-3\)
\(10x=-3+2\)
\(10x=1\)
\(x=1:10\)
\(x=\frac{1}{10}\)
\(4\left(x+3\right)-2\left(7-3x\right)=-3\)
\(\Leftrightarrow4x+12-14+6x=-3\)
\(\Leftrightarrow10x-2=-3\)
\(\Leftrightarrow10x=-1\)
\(\Leftrightarrow x=\frac{-1}{10}\)
Vậy \(x=\frac{-1}{10}\)
dễ thế còn gì lớp 5 hay sao mà ko biết làm
Bài giải
\(4\left(x+3\right)-2\left(7-3x\right)=-3\)
\(4x+12-14+6x=-3\)
\(10x-2=-3\)
\(10x=-1\)
\(x=-\frac{1}{10}\)
Bài làm :
Ta có :
\(4\left(x+3\right)-2\left(7-3x\right)=-3\)
\(\Leftrightarrow4x+12-14+6x=-3\)
\(\Leftrightarrow10x-2=-3\)
\(\Leftrightarrow10x=-1\)
\(\Leftrightarrow x=\frac{-1}{10}=-0,1\)
Vậy x=- 0,1
