Question

Tìm x

4/5 - giá trị tuyệt đối của x + 1/2 = 1/4

Answer 1

\(\dfrac{4}{5}-\left|x+\dfrac{1}{2}\right|=\dfrac{1}{4}\)

\(\Leftrightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{11}{20}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{11}{20}\\x+\dfrac{1}{2}=-\dfrac{11}{20}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{20}\\x=-\dfrac{21}{20}\end{matrix}\right.\)

Answer 2

\(\Rightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{11}{20}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{11}{20}\left(x\ge-\dfrac{1}{2}\right)\\x+\dfrac{1}{2}=-\dfrac{11}{20}\left(x< -\dfrac{1}{2}\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{20}\left(tm\right)\\x=-\dfrac{21}{20}\left(tm\right)\end{matrix}\right.\)

Answer 3

Mik ko hiểu đề lắm

Answer 4

x=1/4-1/2

x=-1/2

 vậy giá trị tuyệt đối x= -1/2 hoặc 1/2

Answer 5

\(\dfrac{4}{5}-\left|x+\dfrac{1}{2}\right|=\dfrac{1}{4}\)

\(\Rightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{11}{20}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{11}{20}\\x+\dfrac{1}{2}=-\dfrac{11}{20}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{20}\\x=-\dfrac{21}{20}\end{matrix}\right.\)