Question

Tìm x

(2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)

Answer 1

\(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)

\(\Rightarrow2x^2-5x-12+x^2-7x+10=3x^2-17x+20\)

\(\Rightarrow5x=22\Rightarrow x=\dfrac{22}{5}\)

Answer 2

Ta có: \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)

\(\Leftrightarrow2x^2-8x+3x-12+x^2-7x+10=3x^2-12x-5x+20\)

\(\Leftrightarrow3x^2-12x-2=3x^2-17x+20\)

\(\Leftrightarrow5x=22\)

hay \(x=\dfrac{22}{5}\)

Answer 3