Question

tìm x
(2x+3)² - (x-1)² = 0

 

Answer 1

\(\left(2x+3-x+1\right)\left(2x+3+x+1\right)=0\Leftrightarrow\left(x+4\right)\left(3x+4\right)=0\Leftrightarrow x=-4;x=-\dfrac{4}{3}\)

Answer 2

(2x + 3)² - (x - 1)² = 0

(2x + 3 - x + 1)(2x + 3 + x - 1) = 0

(x + 4)(3x + 2) = 0

x + 4 = 0 hoặc 3x + 2 = 0

*) x + 4 = 0

x = 0 - 4

x = -4

*) 3x + 2 = 0

3x = 0 - 2

3x = -2

x = -2/3

Vậy x = -4; x = -2/3