Question

Tìm x

2^x-1+5.2^x-2=7/32

Answer 1

2^x-1+5.2^x-2=7/32

=>2.2^x-2+5.2^x-2=7/32

=7.2^x-2=7/32

=>2^x-2=1/32

=>2^x-2=2^-5

=>x-2=-5

=>x=-3

vậy x=-3

k nha

Answer 2

\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

\(\Rightarrow2.2^{x-2}+5.2^{x-2}=\frac{7}{32}\)

\(=7.2^{x-2}=\frac{7}{32}\)

\(\Rightarrow2^{x-2}=\frac{1}{32}\)

\(=2^{x-2}=2^{-5}\)

\(\Rightarrow x-2=-5\)

\(\Rightarrow x=-3\)

Answer 3

2
x-1+5.2
x-2=7/32
=>2.2
x-2+5.2
x-2=7/32
=7.2
x-2=7/32
=>2
x-2=1/32
=>2
x-2=2
-5
=>x-2=-5
=>x=-3
vậy x=-3