\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\)
\(\frac{2}{3x}-\frac{1}{4}=\frac{4}{5}-\frac{7}{x}+2\)
\(\frac{2}{3x}+\frac{7}{x}=\frac{4}{5}+\frac{1}{4}+2\)
\(\frac{2x}{3x^2}+\frac{21x}{3x^2}=\frac{61}{20}\)
\(\frac{2x+21x}{3x^2}=\frac{61}{20}\)
\(\Rightarrow20\left(2x+21x\right)=61.3x^2\)
\(\Rightarrow40x+420x=183x^2\)
\(\Rightarrow460x=183x^2\)
\(\Rightarrow\frac{460}{183}=\frac{x^2}{x}\)
\(\Rightarrow x=\frac{460}{183}\)
Ta có: \(\frac{2}{3}x-\frac{1}{4}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\)
\(\Leftrightarrow\frac{2}{3}x-\frac{1}{4}=\frac{4}{5}-\frac{7}{x}+2\)
\(\Rightarrow\frac{2}{3}x-\frac{1}{4}=\frac{14}{5}-\frac{7}{x}\)
\(\Rightarrow\frac{2}{3}x+\frac{7}{x}=\frac{14}{5}+\frac{1}{4}\)
\(\Rightarrow\frac{2}{3}x+\frac{1}{7}x=\frac{51}{20}\)
Giải tiếp đi nha
