\(128-3.\left(x+4\right)=23\)
\(128-3x-12=23\)
\(116-3x=23\)
\(3x=116-23\)
\(3x=93\)
\(x=31\)
128 - 3 . ( x + 4 ) = 23
=> 3 . ( x + 4 ) = 128 - 23
=> 3 . ( x + 4 ) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
128-3.(x+4)=23
3.(x+4)=128-23
3.x(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31