Question

tìm x:

   

Answer 1

\(2x\left(x-2\right)-\left(x-2\right)^2=0\\ \left(x-2\right)\left(2x-x+2\right)=0\\ \left(x-2\right)\left(x+2\right)=0\\ x^2-4=0\\ x^2=4\\ x=2;x=-2\)

Answer 2

\(2x\left(x-2\right)-\left(2-x\right)^2=0\)

\(\Rightarrow2x\left(x-2\right)-\left(x-2\right)^2=0\)

\(\Rightarrow\left(x-2\right)\left(2x-x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\2x-x+2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)

 

Answer 3

\(2x(x-2)-(2-x)^2=0\)

\(<=>(x-2)( 2x-x+2) =0\)

\(<=>(x-2)(x+2)=0\)

\(< =>\left[{}\begin{matrix}x-2=0\\x+2=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)