Question

Tìm x; y ; z biết :

\(\left(\dfrac{-1}{25}\right)^{14}:\left(2x-1\right)^2=\left(\dfrac{1}{5}\right)^{26}\)

Answer 1

^13 hay ^14 zậy bạn

Answer 2

\(\left(\frac{-1}{25}\right)^{14}:\left(2x-1\right)^2=\left(\frac{1}{5}\right)^{26}\)

=> (2x-1)² = \(\left(\frac{-1}{25}\right)^{14}:\left(\frac{1}{5}\right)^{26}\)

=> ( 2x - 1 )² = \(\left(\frac{-1}{25}\right)^{14}:\left(\frac{1}{25}\right)^{13}\)

=> ( 2x - 1 )² = \(\left[\left(\frac{-1}{25}\right)^{13}.\left(\frac{-1}{25}\right)\right]:\left(\frac{1}{25}\right)^{13}\)

=> ( 2x - 1 )² = \(\frac{1}{25}\)

=> ( 2x - 1 )^2 = \(\left(\frac{1}{5}\right)^2\)

=> \(\hept{\begin{cases}2x-1=\frac{1}{5}\\2x-1=\frac{-1}{5}\end{cases}}\)

=> \(\hept{\begin{cases}2x=\frac{1}{5}+1\\2x=\frac{-1}{5}+1\end{cases}}\)

=> \(\hept{\begin{cases}x=\frac{3}{5}\\x=\frac{2}{5}\end{cases}}\)

Vậy x = 3/5 hay x = 2/5