Question

Tìm x , y biết x và y thuộc N

\(x+y=x^2+\sqrt{y}=1\)

 

Answer 1

\(x+y=x^2+\sqrt{y}=1\)

\(\left\{y=1-x;x^2+\sqrt{y}=1\right\}\)

\(\Rightarrow x=\left\{0;1\right\}\)\(;\)\(y=\left\{1;0\right\}\)

Answer 2

\(x+y=x^2\sqrt{y}=1\)

\(\hept{ }y=1-x;x^2+\sqrt{y}=1\)

\(\Rightarrow x=\left\{0;1\right\};y=\left\{0;1\right\}\)