=>x(2y+1)+y+1/2=3/2
=>(y+1/2)(2x+1)=3/2
=>(2x+1)(2y+1)=3
=>\(\left(2x+1;2y+1\right)\in\left\{\left(1;3\right);\left(3;1\right);\left(-1;-3\right);\left(-3;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(0;1\right);\left(1;0\right);\left(-1;-2\right);\left(-2;-1\right)\right\}\)