Question

Tìm x (x+2).(x-3)-(x-1).(x+5)=4x-1

Answer 1

Ta có :

x(x+2).(x-3)-(x-1).(x+5) - 4x + 1 =0

<=> x^3 - 3x^2 + 2x^2 - 6x - x^2 -5x+x +5 -4x + 1= 0

<=> x^3 - 2x^2 - 14x + 6= 0

<=> x(x-1)^2 -15+ 6 = 0

Answer 2

Ta có: \(\left(x+2\right)\cdot\left(x-3\right)-\left(x-1\right)\left(x+5\right)=4x-1\)

\(\Leftrightarrow x^2-x-6-x^2-4x+5-4x+1=0\)

\(\Leftrightarrow-9x=0\)

hay x=0