\(\left(x+\dfrac{2}{9}\right)^2=\dfrac{4}{81}\\ \left(x+\dfrac{2}{9}\right)^2=\left(\dfrac{2}{9}\right)^2\\ x+\dfrac{2}{9}=\dfrac{2}{9}\\ x=\dfrac{2}{9}-\dfrac{2}{9}\\ x=0\)
Mình bổ sung thêm TH2 nữa.
\(\left(x+\dfrac{2}{9}\right)^2=\left(-\dfrac{2}{9}\right)^2\\ x+\dfrac{2}{9}=-\dfrac{2}{9}\\ x=-\dfrac{2}{9}-\dfrac{2}{9}\\ x=-\dfrac{4}{9}\)
\(...\Rightarrow\left(x+\dfrac{2}{9}\right)^2=\left(\dfrac{2}{9}\right)^2\)
\(\Rightarrow x+\dfrac{2}{9}=\dfrac{2}{9}\Rightarrow x=0\)