x2 + 5x = 6
<=> x2 + 5x - 6 = 0
<=> x2 - x + 6x - 6 = 0
<=> x(x - 1) + 6(x - 1) = 0
<=> (x + 6)(x - 1) = 0
<=> \(\left[{}\begin{matrix}x+6=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=1\end{matrix}\right.\)
Ta có: \(x^2+5x=6\)
\(\Leftrightarrow x^2+5x-6=0\)
\(\Leftrightarrow\left(x+6\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=1\end{matrix}\right.\)