Question

Tìm x :

x+1=(x+1)^2

Answer 1

x+1=(x+1)²

<=> x+1-x²-2x-1=0

<=> -x²-x=0

<=> -x.(x+1)=0

<=> -x=0 <=> x=0

hoặc x+1 = 0 <=> x=-1

Answer 2

\(x+1=\left(x+1\right)^2\)

=>  \(x+1=x^2+2x+1\)

=> \(1-1=x^2+2x-x\)

=> \(0=x^2-x\)

=> \(x^2=x\)

=> \(x=0,x=1\)