=> 4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25
(X+1) + (X + 2) + (X + 3) + (X + 4) = 110
<=>(x+x+x+x)+(1+2+3+4)=110
<=>4x+10=110
<=>4x=100
<=>x=25
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+\left(x+4\right)=10\)
\(4x+1+2+3+4=10\)
\(4x+10=10\)
\(4x=10-10=0\Rightarrow x=0\) Vậy x=0
(X + 1) + (X + 2) + (X + 3) + (X + 4) = 110
=> X + 1 + X + 2 + X + 3 + X + 4 = 110
=> (X + X + X + X) + (1 + 2 + 3 + 4) = 110
=> 4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25
=> 4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25
Theo bài ra , ta có :
4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25
Đáp số : 25
=> 4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25