Question

Tìm x

X + X x \(\dfrac{1}{3}\) + \(\dfrac{5}{18}=\dfrac{7}{6}\)

Answer 1

X + X x \(\dfrac{1}{3}\) + \(\dfrac{5}{18}\) = \(\dfrac{7}{6}\)

X x \(\dfrac{4}{3}\)                 = \(\dfrac{7}{6}-\dfrac{5}{18}\)

X x \(\dfrac{4}{3}\)                 = \(\dfrac{8}{9}\)

X                        = \(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{2}{3}\)                  

Answer 2

\(x\cdot\left(\dfrac{1}{3}+1\right)=\dfrac{21}{18}-\dfrac{5}{18}=\dfrac{16}{18}=\dfrac{8}{9}\)

\(x=\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{4\cdot2\cdot3}{3\cdot3\cdot4}=\dfrac{2}{3}\)