Question

Tìm x :

(x-3)\(^2\)+x(1-x)=3

Answer 1

`(x-3)^2+x(1-x)=3`

`<=>x^2-6x+9+x-x^2-3=0`

`<=>-5x+6=0`

`<=>5x=6`

`<=>x=6/5`

Vậy `S={6/5}`

Answer 2

Khai triển ra ta có :

x^2-6x+9 + x - x^2 =3

<=> -5x = -6

<=> x=6/5

Answer 3

Ta có: \(\left(x-3\right)^2+x\left(1-x\right)=3\)

\(\Leftrightarrow x^2-6x+9+x-x^2-3=0\)

\(\Leftrightarrow-5x+6=0\)

hay \(x=\dfrac{6}{5}\)