(2x+ 1)(y + 2) = 10 = 1.10 = 5.2
Vì 2x+ 1 lẻ => 2x + 1 = 1 hoặc 2x + 1 = 5
TH1: 2x + 1= 1 => x = 0
y + 2= 10 => y = 8
TH2: 2x+ 1 = 5 => x = 2
y + 2= 2 => y = 0
Vậy (x , y) \(\in\) { (0 ; 8) ; (2 ; 0 ) }
(2x+1)(y+2)=10=1.10=5.2
Vì 2x+1 lẻ suy ra 2x+1=1 hay 2x+1=5
th1:2x+1=1 suy ra x=0
y+2=10 suy ra y=8
th2:2x+1=5 suy ra x=2
y+2=2 suy ra y=0