a,\(\left(3x-4\right).2^3=64\)
(=) \(\left(3x-4\right)=64:8\)
(=) \(3x-4=8\)
(=) \(3x=8+4\)
(=) \(3x=12\)
(=) \(x=12:3\)
(=) \(x=4\)
b, Ta có \(2^3.3^2-4x=4^3\)
(=) \(8.9-4x=64\)
(=) \(72-4x=64\)
(=) \(4x=72-64\)
(=) \(4x=8\)
(=) \(x=8:4\)
(=) \(x=2\)
a) ( 3x - 4 ) . 23 = 64
=> ( 3x - 4 ) = 64 : 23
=> ( 3x - 4 ) = 26 : 23
=> ( 3x - 4 ) = 23
=> 3x - 4 = 8
=> 3x = 12
=> x = 4
b) 23 . 32 - 4x = 43
=> 8 . 9 - 4x = 64
=> 72 - 4x = 64
=> 4x = 8
=> x = 2
(3x - 4 ) = 64 : 23 ( 8 )
3x - 4 = 8
3x = 8 + 4 = 12 x = 12 : 3 = 4
