\(\frac{-3}{5}+\frac{6}{7}< \frac{x}{2}\le\frac{3}{14}+\frac{7}{10}\)
\(< =>\frac{9}{35}< \frac{x}{2}\le\frac{32}{35}\left(x\in Z\right)\)
\(< =>\frac{18}{70}< \frac{35\cdot x}{70}\le\frac{64}{70}\)
\(< =>18< 35.x\le64\)
\(=>x=1\)
Vậy x=1
Mình nghĩ là thế nhé