Question

tìm x sao cho

7/(3-x)=11/(x+5)

Answer 1

Ta có

\(\frac{7}{3-x}=\frac{11}{x+5}\)

<=>\(7\left(x+5\right)=11\left(3-x\right)\)

<=>\(7x+35=33-11x\)

<=>\(7x+11x=33-35\)

<=>\(18x=-2\)

<=>\(x=-\frac{1}{9}\)

Answer 2

Ta có:\(\frac{7}{3-x}=\frac{11}{x+5}\)

=> 7(x+5)=11(3-x)

     7x+7.5=11.3-11x

     7x+35=33-11x

     7x+11x+35=33

     18x=33-35=-2

      x=(-2):18=\(\frac{-2}{18}=\frac{-1}{9}\)

Tick nha