Question

tìm x bt :

a.2|3x-1| + 1 = 5 

giúp mik vs;-;

Answer 1

\(a,2\left|3x-1\right|+1=5\)

\(\Leftrightarrow2\left|3x-1\right|=4\)

\(\Leftrightarrow\left|3x-1\right|=2\Leftrightarrow\left[{}\begin{matrix}3x-1=2\\3x-1=-2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)

Answer 2

2.l3x-1l+1=5
=>2.l3x-1l=4
=>l3x-1l=2
TH1:3x-1=2 =>x=1
TH2:3x-1=-2 =>x=-1/3