\(\left|x+2\right|-6x=1\left(đk:x\ge-\dfrac{1}{6}\right)\)
\(\Leftrightarrow x+2=6x+1\left(do.x\ge-\dfrac{1}{6}\right)\)
\(\Leftrightarrow5x=1\Leftrightarrow x=\dfrac{1}{5}\left(tm\right)\)
\(\left|x+2\right|-6x=1\)
\(\Leftrightarrow\left|x+2\right|=6x+1\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=6x+1\left(x\ge-2\right)\\x+2=-6x-1\left(x< -2\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-5x=-1\\7x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\left(nhận\right)\\x=\dfrac{-3}{7}\left(loại\right)\end{matrix}\right.\)
