x-7-(11-3x)=22
x-7-11+3x=22
x+3x=22+7+11
4x=40
x=40:4=10
Vậy x cần tìm là 10
\(x-7-(11-3x)=22\)
\(x-7-11+3x=22\)
\((x+3x)-7-11=22\)
\(4x-7=22+11\)
\(4x-7=33\)
\(4x=33+7\)
\(4x=40\)
\(x=40:4\)
\(x=10\)
Vậy x=10
~ Hok tốt a~
\(x-7-\left(11-3x\right)=22\)
\(\Rightarrow x-7-11+3x=22\)
\(\Rightarrow\left(x+3x\right)+\left(-7-11\right)=22\)
\(\Rightarrow4x-18=22\)
\(\Rightarrow4x=22+18\)
\(\Rightarrow4x=40\)
\(\Rightarrow x=40:4\)
\(\Rightarrow x=10\)
Vậy x = 10
_Chúc bạn học tốt_
x - 7 - (11 - 3x) = 22
=> x - 7 - 11 + 3x = 22
=> x + 3x = 22 + 7 + 11
=> 4x = 40
=> x = 40 : 4
=> x = 10
Vậy x = 10