\(\Leftrightarrow x^2+2x-15-\left(x^2+3x-28\right)+2x=11\)
\(\Leftrightarrow x^2+4x-15-x^2-3x+28=11\)
=>x+13=11
hay x=-2
`(x-3).(x+5)- (x-4)(x+7)+2x = 11`
`x^2 +2x-15 - x^2 -3x+28+2x=11`
`(2x-3x+2x)+(-15+28)=11`
`x +13=11`
`x=11-13`
`x=-2`
Vậy `x=-2``