Xet |x-2| = x-2
=> \(x-2-\left(2x+\frac{1}{4}\right)=x-1\)
=> \(x-2-2x-\frac{1}{4}=x-1\)
=> \(-x-\frac{7}{4}=x+1\)
=> \(\frac{3}{4}=2x=>x=\frac{3}{8}\)
Xet | x-2 | = -(x-2) = -x+2
=> \(-x+2-\left(2x+\frac{1}{4}\right)=x-1\)
=> \(-x+2-2x-\frac{1}{4}=x-1\)
=> \(-3x+\frac{7}{4}\)=x-1
=> \(\frac{11}{4}=4x=>x=\frac{11}{16}\)