a) 6(x+1)-3=2(x+2)+11
6x + 6 - 3= 2x+ 4+11
6x-2x +6-3= 4+11
4x +6-3= 15
4x+6= 15+3
4x+6= 18
4x= 18-6
4x= 12
x= 12:4
x=3
Vậy...
c) ( x+2 ) \(⋮\)( 2x-1)
=> 2x-1 \(⋮\)2x-1
=> ( x+2 ) - ( 2x-1)\(⋮\)2x-1
=> 2( x+2) - ( 2x-1) \(⋮\)2x-1
=> (2x+4)-(2x-1) \(⋮\)2x-1
=> 2x+4 - 2x+1 \(⋮\)2x-1
=> 5 \(⋮\)2x-1
=> 2x-1\(\in\)Ư(5) = { 1;5; -1;-5}
Xong b tự thay nha
b) Ta có : \(\frac{2x-1}{8}=\frac{x+7}{24}\)
\(\Rightarrow\left(2x-1\right).24=8\left(x+7\right)\)
\(48x-24=8x+56\)
\(48x-8x-24=56\)
\(40x-24=56\)
\(40x=56+24\)
\(40x=80\)
\(x=80:40\)
\(x=2\)
Vậy x=2
a) \(6\left(x+1\right)-3=2\left(x+2\right)+11\)
\(\Leftrightarrow6x+6-3=2x+4+11\)
\(\Leftrightarrow6x+3=2x+15\)
\(\Leftrightarrow6x-2x=15-3\)
\(\Leftrightarrow4x=12\)
\(\Leftrightarrow x=3\)
Vậy x=3
b) \(\frac{2x-1}{8}=\frac{x+7}{24}\)
\(\Leftrightarrow24\left(2x-1\right)=8\left(x+7\right)\)
\(\Leftrightarrow48x-24=8x+56\)
\(\Leftrightarrow48x-8x=56+24\)
\(\Leftrightarrow40x=80\)
\(\Leftrightarrow x=2\)
Vậy x=2