15(x + 1) + 75 = 110
=> 15x + 15 + 75 = 110
=> 15x + 90 = 110
=> 15x = 20
=> x = 1,5
vậy_
a)
15 ( x + 1 ) + 75 = 110
15 ( x + 1 ) = 35
x + 1 = 7/3
x = 4/3
b)
\(2^x\cdot5+2=47\)
\(2^x\cdot5=45\)
\(2^x=9\)
\(x=3,169925001\)
?? WTF đề ??
a,15(x+10)=110-75=15(x+10)=35
x+10=7/3
x=7/3-10=-21/3
\(a)\)\(15\left(x+1\right)+75=110\)
\(15\left(x+1\right)=110-75\)
\(15\left(x+1\right)=35\)
\(x+1=35:15\)
\(x+1=\frac{7}{3}\)
\(x=\frac{7}{3}-1\)
\(x=\frac{4}{3}\)
\(b)\)\(2^x.5+2=47\)
\(2^x.5=47-2\)
\(2^x.5=45\)
\(2^x=45:5\)
\(2^x=9\)
\(\Rightarrow x=3\)\(\text{hoặc}\)\(x=\left(-3\right)\)
a) \(15\left(x+1\right)+75=110\) b) \(2^x\cdot5+2=47\)
\(15\left(x+1\right)=110-75\) \(2^x\cdot5=47-2\)
\(15\left(x+1\right)=35\) \(2^x\cdot5=45\)
\(x+1=35:15\) \(2^x=45:5\)
\(x+1=\frac{7}{3}\) \(2^x=9\)
\(x=\frac{7}{3}-1\) .....................................
\(x=\frac{4}{3}\)
\(15.\left(x+1\right)+75=110\)
\(15.\left(x+1\right)=110-75\)
\(15.\left(x+1\right)=35\)
\(=>...\)
\(15.\left(x+1\right)+75=110\)
\(15.\left(x+1\right)=110-75=35\)
\(x+1=\frac{7}{3}\)
\(x=\frac{4}{3}\)