Question

Tìm x biết

a. 15.(x+1) +75=110

b.2^x.5+2=47

Answer 1

15(x + 1) + 75 = 110

=> 15x + 15 + 75 = 110

=> 15x + 90 = 110

=> 15x = 20

=> x = 1,5

vậy_

Answer 2

a) 

15 ( x + 1 ) + 75 = 110

15 ( x + 1 ) = 35

x + 1 = 7/3

x = 4/3

b) 

\(2^x\cdot5+2=47\)

\(2^x\cdot5=45\)

\(2^x=9\)

\(x=3,169925001\)

?? WTF đề ??

Answer 3

a,15(x+10)=110-75=15(x+10)=35

x+10=7/3

x=7/3-10=-21/3

Answer 4

\(a)\)\(15\left(x+1\right)+75=110\)

\(15\left(x+1\right)=110-75\)

\(15\left(x+1\right)=35\)

\(x+1=35:15\)

\(x+1=\frac{7}{3}\)

\(x=\frac{7}{3}-1\)

\(x=\frac{4}{3}\)

\(b)\)\(2^x.5+2=47\)

\(2^x.5=47-2\)

\(2^x.5=45\)

\(2^x=45:5\)

\(2^x=9\)

\(\Rightarrow x=3\)\(\text{hoặc}\)\(x=\left(-3\right)\)

Answer 5

a) \(15\left(x+1\right)+75=110\)                             b) \(2^x\cdot5+2=47\)

\(15\left(x+1\right)=110-75\)                                      \(2^x\cdot5=47-2\)

\(15\left(x+1\right)=35\)                                                     \(2^x\cdot5=45\)

\(x+1=35:15\)                                                          \(2^x=45:5\)

\(x+1=\frac{7}{3}\)                                                                  \(2^x=9\)

\(x=\frac{7}{3}-1\)                                            .....................................

\(x=\frac{4}{3}\)

Answer 6

\(15.\left(x+1\right)+75=110\)

\(15.\left(x+1\right)=110-75\)

\(15.\left(x+1\right)=35\)

\(=>...\)

Answer 7

\(15.\left(x+1\right)+75=110\)

\(15.\left(x+1\right)=110-75=35\)

\(x+1=\frac{7}{3}\)

\(x=\frac{4}{3}\)