Question

tìm x biết

\(6x^2-\left(2x+5\right)\left(3x-2\right)=7\)

Answer 1

`6x^2 - (2x+5)(3x-2) = 7`

`<=> 6x^2 - (6x^2 + 15x - 4x - 10) = 7`

`<=> 6x^2 - 6x^2 - 15x + 4x + 10 = 7`

`<=> -11x = -3`

`=> x = 3/11`

Answer 2

\(6x^2-6x^2+4x-15x+10=7\)

\(-11x+10=7\)

\(-11x=7-10\)

\(-11x=-3\)

\(x=\dfrac{-3}{-11}\)

\(x=\dfrac{3}{11}\)

Answer 3

\(6 x ^2 − ( 2 x + 5 ) ( 3 x − 2 ) = 7\)

\(⇔6x^2-(6x^2-4x+15x-10)=7\)

\(⇔6x^2-6x^2+4x-15x+10=7\)

\(⇔-11x=-3\)

\(⇔x=-3:(-11)\)

\(\text{⇔}\text{x}=\dfrac{3}{11}\)