Question

Tìm x biết

\(^{^{4^{x+1}-41=23}}\)

Answer 1

\(4^{x+1}-41=23\Leftrightarrow4^{x+1}=64=2^6=\left(2^2\right)^4=4^4\)

Suy ra \(x+1=4\Leftrightarrow x=3\)

Answer 2

chết nhầm!sorry nhiều=(

\(4^{x+1}-41=23\Leftrightarrow4^{x+1}=64=2^6=\left(2^2\right)^3=4^3\)

Suy ra \(x+1=3\Leftrightarrow x=2\)

Answer 3

\(4^{x+1}-41=23\)

\(4^{x-1}=64\)

\(4^{x-1}=4^3\)

\(\Rightarrow x-1=3\)

\(x=4\)