Question

tìm x biết:

3^x+1 - 3^x = 2

pleaseeeee giải giúp mình nha

Answer 1

x=0

~~~~~~~

^_^

Answer 2

\(3^{x+1}-3^x=2\)

\(3^x\cdot3-3^x=2\)

\(3^x\left(3-1\right)=2\)

\(3^x\cdot2=2\)

\(3^x=1\)

\(\Rightarrow x=0\)

Answer 3

\(3^{x+1}-3^x=2\)

\(3^x.\left(3-1\right)=2\)

\(3^x.2=2=>3^x=1=>x=0\)

Answer 4

3\(^{x+1}\)-3\(^x\)= 2

3\(^x\). 3 - 3\(^x\). 1 = 2

3\(^x\). ( 3 - 1 ) = 2

       3\(^x\). 2 = 2

               3\(^x\)= 2 \(\div\)2

               3\(^x\)= 1

               3\(^x\)= 3\(^0\)

                 x = 0