2x + 2x+1 +2x+2 + 2x+3 = 120
Suy ra 2x .1 + 2x . 2 + 2x . 22 + 2x . 23 = 120
Suy ra 2x .( 1 + 2 + 4 + 8 ) = 120
Suy ra 2x . 15 = 120
Suy ra 2x = 120 : 15
Suy ra 2x = 8
Suy ra 2x = 23
Do đó x = 3
Vậy x = 3
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=120\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=120\)
\(\Rightarrow2^x+2^x.2+2^x.4+2^x.8=120\)
\(\Rightarrow2^x\left(1+2+4+8\right)=120\)
\(\Rightarrow2^x.15=120\)
\(\Rightarrow2^x=120:15\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)