Tham khảo:
TH1: Nếu x>2 ta có: x-2 + 2x-3 =2x + 1
<=> x=6 .
TH2: Nếu \(\dfrac{3}{2}\) ≤x≤2 ta có: 2 - x + 2x -3 = 2x+1
<=> x=-2 (loại)
TH3: x<\(\dfrac{3}{2}\) ta có : 2-x+3-2x= 2x+1
<=> x=\(\dfrac{4}{5}\)
Vậy : x=6 ; x=\(\dfrac{4}{5}\)
biết f(x)=x^2+2x+3/5 2x^3+3 ; g(x) = -2x^2-1/2x^3 -3x +6
tìm h(x) = 2f(x) - 1/2g(x)
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
Tìm x biết:
a) 3x-|2x+1|=2
b)2.|5x-3|-2x=14
c)|x+1|+|x+2|+|x+3|=4x
d)|x-2|+|3-2x|=2x+1
e)|x-3|=(-2).|x+4|
tìm x biết 2(x-1)-3(2x+2)-(2x+3)=16
Tìm x biết :
2x|2-x|+3|x+1|-x+1=2x
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
tìm x biết
a.3x +1/2 (x-1)=x+7(1-x)
b. 4x(x+3)-2=(2x+3)(2x-3)
Tìm x, biết: 2.(x-1) - 3.(2x+2) - 4.(2x+3)=16
Tìm x biết 2(x-1)-3(2x+2)-4(2x+3)=16
